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s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 1 6 sam87ri instruction set overview the sam87ri instruction set is designed to support the large register file. it includes a full complement of 8-bit arithmetic and logic operations. there are 41 instructions. no special i/o instructions are necessary because i/o control and data registers are mapped directly into the register file. flexible instructions for bit addressing, rotate, and shift operations complete the powerful data manipulation capabilities of the sam87ri instruction set. register addressing to access an individual register, an 8-bit address in the range 0-255 or the 4-bit address of a working register is specified. paired registers can be used to construct 13-bit program memory or data memory addresses. for detailed information about register addressing, please refer to section 2, "address spaces". addressing modes there are six addressing modes: register (r), indirect register (ir), indexed (x), direct (da), relative (ra), and immediate (im). for detailed descriptions of these addressing modes, please refer to section 3, "addressing modes".
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 2 table 6- 1. instruction group summary mnemonic operands instruction load instructions clr dst clear ld dst,src load ldc dst,src load program memory lde dst,src load external data memory ldcd dst,src load program memory and decrement lded dst,src load external data memory and decrement ldci dst,src load program memory and increment ldei dst,src load external data memory and increment pop dst pop from stack push src push to stack arithmetic instructions adc dst,src add with carry add dst,src add cp dst,src compare dec dst decrement inc dst increment sbc dst,src subtract with carry sub dst,src subtract logic instructions and dst,src logical and com dst complement or dst,src logical or xor dst,src logical exclusive or
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 3 table 6- 1. instruction group summary (continued) mnemonic operands instruction program control instructions call dst call procedure iret interrupt return jp cc,dst jump on condition code jp dst jump unconditional jr cc,dst jump relative on condition code ret return bit manipulation instructions tcm dst,src test complement under mask tm dst,src test under mask rotate and shift instructions rl dst rotate left rlc dst rotate left through carry rr dst rotate right rrc dst rotate right through carry sra dst shift right arithmetic cpu control instructions ccf complement carry flag di disable interrupts ei enable interrupts idle enter idle mode nop no operation rcf reset carry flag scf set carry flag stop enter stop mode
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 4 flags register (flags) the flags register flags contains eight bits that describe the current status of cpu operations. four of these bits, flags.4?flags.7, can be tested and used with conditional jump instructions . flags register can be set or reset by instructions as long as its outcome does not affect the flags, such as, load instruction. logical and arithmetic instructions such as, and, or, xor, add, and sub can affect the flags register. for example, the and instruction updates the zero, sign and overflow flags based on the outcome of the and instruction. if the and instruction uses the flags register as the destination, then simultaneously, two write will occur to the flags register producing an unpredictable result. system flags register (flags) d5h, r/w .7 .6 .5 lsb msb .4 .3 .2 .1 .0 not mapped carry flag (c) zero flag (z) sign flag (s) overflow flag (v) figure 6-1. system flags register (flags) flag descriptions overflow flag (flags.4, v) the v flag is set to "1" when the result of a two's-complement operation is greater than + 127 or less than ? 128. it is also cleared to "0" following logic operations. sign flag (flags.5, s) following arithmetic, logic, rotate, or shift operations, the sign bit identifies the state of the msb of the result. a logic zero indicates a positive number and a logic one indicates a negative number. zero flag (flags.6, z) for arithmetic and logic operations, the z flag is set to "1" if the result of the operation is zero. for operations that test register bits, and for shift and rotate operations, the z flag is set to "1" if the result is logic zero. carry flag (flags.7, c) the c flag is set to "1" if the result from an arithmetic operation generates a carry-out from or a borrow to the bit 7 position (msb). after rotate and shift operations, it contains the last value shifted out of the specified register. program instructions can set, clear, or complement the carry flag.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 5 instruction set notation table 6-2. flag notation conventions flag description c carry flag z zero flag s sign flag v overflow flag 0 cleared to logic zero 1 set to logic one * set or cleared according to operation ? value is unaffected x value is undefined table 6- 3. instruction set symbols symbol description dst destination operand src source operand @ indirect register address prefix pc program counter flags flags register (d5h) # immediate operand or register address prefix h hexadecimal number suffix d decimal number suffix b binary number suffix opc opcode
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 6 table 6- 4. instruction notation conventions notation description actual operand range cc condition code see list of condition codes in table 6- 6. r working register only rn (n = 0?15) rr working register pair rrp (p = 0, 2, 4, ..., 14) r register or working register reg or rn (reg = 0?255, n = 0?15) rr register pair or working register pair reg or rrp (reg = 0?254, even number only, where p = 0, 2, ..., 14) ir indirect working register only @rn (n = 0?15) ir indirect register or indirect working register @rn or @reg (reg = 0?255, n = 0?15) irr indirect working register pair only @rrp (p = 0, 2, ..., 14) irr indirect register pair or indirect working register pair @rrp or @reg (reg = 0?254, even only, where p = 0, 2, ..., 14) x indexed addressing mode #reg[rn] (reg = 0?255, n = 0?15) xs indexed (short offset) addressing mode #addr[rrp] (addr = range ?128 to +127, where p = 0, 2, ..., 14) xl indexed (long offset) addressing mode #addr [rrp] (addr = range 0?8191, where p = 0, 2, ..., 14) da direct addressing mode addr (addr = range 0?8191) ra relative addressing mode addr (addr = number in the range +127 to ?128 that is an offset relative to the address of the next instruction) im immediate addressing mode #data (data = 0?255)
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 7 table 6- 5. opcode quick reference opcode map lower nibble (hex) ? 0 1 2 3 4 5 6 7 u 0 dec r1 dec ir1 add r1,r2 add r1,ir2 add r2,r1 add ir2,r1 add r1,im p 1 rlc r1 rlc ir1 adc r1,r2 adc r1,ir2 adc r2,r1 adc ir2,r1 adc r1,im p 2 inc r1 inc ir1 sub r1,r2 sub r1,ir2 sub r2,r1 sub ir2,r1 sub r1,im e 3 jp irr1 sbc r1,r2 sbc r1,ir2 sbc r2,r1 sbc ir2,r1 sbc r1,im r 4 or r1,r2 or r1,ir2 or r2,r1 or ir2,r1 or r1,im 5 pop r1 pop ir1 and r1,r2 and r1,ir2 and r2,r1 and ir2,r1 and r1,im n 6 com r1 com ir1 tcm r1,r2 tcm r1,ir2 tcm r2,r1 tcm ir2,r1 tcm r1,im i 7 push r2 push ir2 tm r1,r2 tm r1,ir2 tm r2,r1 tm ir2,r1 tm r1,im b 8 ld r1, x, r2 b 9 rl r1 rl ir1 ld r2, x, r1 l a cp r1,r2 cp r1,ir2 cp r2,r1 cp ir2,r1 cp r1,im ldc r1, irr2, xl e b clr r1 clr ir1 xor r1,r2 xor r1,ir2 xor r2,r1 xor ir2,r1 xor r1,im ldc r2, irr2, xl c rrc r1 rrc ir1 ldc r1,irr2 ld r1, ir2 h d sra r1 sra ir1 ldc r2,irr1 ld ir1,im ld ir1, r2 e e rr r1 rr ir1 ldcd r1,irr2 ldci r1,irr2 ld r2,r1 ld r2,ir1 ld r1,im ldc r1, irr2, xs x f call irr1 ld ir2,r1 call da1 ldc r2, irr1, xs
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 8
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 9 table 6- 5. opcode quick reference (continued) opcode map lower nibble (hex) ? 8 9 a b c d e f u 0 ld r1,r2 ld r2,r1 jr cc,ra ld r1,im jp cc,da inc r1 p 1 p 2 e 3 r 4 5 n 6 idle i 7 stop b 8 di b 9 ei l a ret e b iret c rcf h d scf e e ccf x f ld r1,r2 ld r2,r1 jr cc,ra ld r1,im jp cc,da inc r1 nop
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 10 condition codes the opcode of a conditional jump always contains a 4-bit field called the condition code (cc). this specifies under which conditions it is to execute the jump. for example, a conditional jump with the condition code for "equal" after a compare operation only jumps if the two operands are equal. condition codes are listed in table 6- 6. the carry (c), zero (z), sign (s), and overflow (v) flags are used to control the operation of conditional jump instructions. table 6- 6. condition codes binary mnemonic description flags set 0000 f always false ? 1000 t always true ? 0111 * c carry c = 1 1111 * nc no carry c = 0 0110 * z zero z = 1 1110 * nz not zero z = 0 1101 pl plus s = 0 0101 mi minus s = 1 0100 ov overflow v = 1 1100 nov no overflow v = 0 0110 * eq equal z = 1 1110 * ne not equal z = 0 1001 ge greater than or equal (s xor v) = 0 0001 lt less than (s xor v) = 1 1010 gt greater than (z or (s xor v)) = 0 0010 le less than or equal (z or (s xor v)) = 1 1111 * uge unsigned greater than or equal c = 0 0111 * ult unsigned less than c = 1 1011 ugt unsigned greater than (c = 0 and z = 0) = 1 0011 ule unsigned less than or equal (c or z) = 1 notes: 1. asterisks (*) indicate condition codes that are related to two different mnemonics but which test the same flag. for example, z and eq are both true if the zero flag (z) is set, but after an add instruction, z would probably be used; after a cp instruction, however, eq would probably be used. 2. for operations involving unsigned numbers, the special condition codes uge, ult, ugt, and ule must be used.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 11 instruction descriptions this section contains detailed information and programming examples for each instruction in the sam87ri instruction set. information is arranged in a consistent format for improved readability and for fast referencing. the following information is included in each instruction description: ? instruction name (mnemonic) ? full instruction name ? source/destination format of the instruction operand ? shorthand notation of the instruction's operation ? textual description of the instruction's effect ? specific flag settings affected by the instruction ? detailed description of the instruction's format, execution time, and addressing mode (s) ? programming example (s) explaining how to use the instruction
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 12 adc ? add with carry adc dst,src operation: dst ? dst + src + c the source operand, along with the setting of the carry flag, is added to the destination operand and the sum is stored in the destination. the contents of the source are unaffected. two's- complement addition is performed. in multiple precision arithmetic, this instruction permits the carry from the addition of low-order operands to be carried into the addition of high-order operands. flags: c: set if there is a carry from the most significant bit of the result; cleared otherwise. z: set if the result is "0"; cleared otherwise. s: set if the result is negative; cleared otherwise. v: set if arithmetic overflow occurs, that is, if both operands are of the same sign and the result is of the opposite sign; cleared otherwise. d: always cleared to "0". h: set if there is a carry from the most significant bit of the low-order four bits of the result; cleared otherwise. format: bytes cycles opcode (hex) addr mode dst src opc dst | src 2 6 12 r r 13 r lr opc src dst 3 10 14 r r 15 r ir opc dst src 3 10 16 r im examples : given: r1 = 10h, r2 = 03h, c flag = "1", register 01h = 20h, register 02h = 03h, and register 03h = 0ah: adc r1,r2 ? r1 = 14h, r2 = 03h adc r1,@r2 ? r1 = 1bh, r2 = 03h adc 01h,02h ? register 01h = 24h, register 02h = 03h adc 01h,@02h ? register 01h = 2bh, register 02h = 03 h adc 01h,#11h ? register 01h = 32h in the first example, destination register r1 contains the value 10h, the carry flag is set to "1", and the source working register r2 contains the value 03h. the statement "adc r1,r2" adds 03h and the carry flag value ("1") to the destination value 10h, leaving 14h in register r1.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 13 add ? add add dst,src operation: dst ? dst + src the source operand is added to the destination operand and the sum is stored in the destination. the contents of the source are unaffected. two's-complement addition is performed. flags: c: set if there is a carry from the most significant bit of the result; cleared otherwise. z: set if the result is "0"; cleared otherwise. s: set if the result is negative; cleared otherwise. v: set if arithmetic overflow occurred, that is, if both operands are of the same sign and the result is of the opposite sign; cleared otherwise. d: always cleared to "0". h: set if a carry from the low-order nibble occurred. format: bytes cycles opcode (hex) addr mode dst src opc dst | src 2 6 02 r r 03 r lr opc src dst 3 10 04 r r 05 r ir opc dst src 3 10 06 r im examples: given: r1 = 12h, r2 = 03h, register 01h = 21h, register 02h = 03h, register 03h = 0ah: add r1,r2 ? r1 = 15h, r2 = 03h add r1,@r2 ? r1 = 1ch, r2 = 03h add 01h,02h ? register 01h = 24h, register 02h = 03h add 01h,@02h ? register 01h = 2bh, register 02h = 03h add 01h,#25h ? register 01h = 46h in the first example, destination working register r1 contains 12h and the source working register r2 contains 03h. the statement "add r1,r2" adds 03h to 12h, leaving the value 15h in register r1.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 14 and ? logical and and dst,src operation: dst ? dst and src the source operand is logically anded with the destination operand. the result is stored in the destination. the and operation results in a "1" bit being stored whenever the corresponding bits in the two operands are both logic ones; otherwise a "0" bit value is stored. the contents of the source are unaffected. flags: c: unaffected. z: set if the result is "0"; cleared otherwise. s: set if the result bit 7 is set; cleared otherwise. v: always cleared to "0". d: unaffected. h: unaffected. format: bytes cycles opcode (hex) addr mode dst src opc dst | src 2 6 52 r r 53 r lr opc src dst 3 10 54 r r 55 r ir opc dst src 3 10 56 r im examples : given: r1 = 12h, r 2 = 03h, register 01h = 21h, register 02h = 03h, register 03h = 0ah: and r1,r2 ? r1 = 02h, r2 = 03h and r1,@r2 ? r1 = 02h, r2 = 03h and 01h,02h ? register 01h = 01h, register 02h = 03h and 01h,@02h ? register 01h = 00h, register 02h = 03h and 01h,#25h ? register 01h = 21h in the first example, destination working register r1 contains the value 12h and the source working register r2 contains 03h. the statement "and r1,r2" logically ands the source operand 03h with the destination operand value 12h, leaving the value 02h in register r1.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 15 call ? call procedure call dst operation: sp ? sp ? 1 @sp ? pcl sp ? sp ?1 @sp ? pch pc ? dst the current contents of the program counter are pushed onto the top of the stack. the program counter value used is the address of the first instruction following the call instruction. the specified destination address is then loaded into the program counter and points to the first instruction of a procedure. at the end of the procedure the return instruction (ret) can be used to return to the original program flow. ret pops the top of the stack back into the program counter. flags: no flags are affected. format: bytes cycles opcode (hex) addr mode dst opc dst 3 18 f6 da opc dst 2 18 f4 irr example s : given: r0 = 15h, r1 = 21h, pc = 1a47h, and sp = 0b2h: call 1521h ? sp = 0b0h (memory locations 00h = 1ah, 01h = 4ah, where 4ah is the address that follows the instruction.) call @rr0 ? sp = 0b0 h (00h = 1ah, 01h = 49h) in the first example, if the program counter value is 1a47h and the stack pointer contains the value 0b2h, the statement "call 1521h" pushes the current pc value onto the top of the stack. the stack pointer now points to memory location 00h. the pc is then loaded with the value 1521h, the address of the first instruction in the program sequence to be executed. if the contents of the program counter and stack pointer are the same as in the first example, the statement "call @rr0" produces the same result except that the 49h is stored in stack location 01h (because the two-byte instruction format was used). the pc is then loaded with the value 1521h, the address of the first instruction in the program sequence to be executed.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 16 ccf ? complement carry flag ccf operation: c ? not c the carry flag (c) is complemented. if c = "1", the value of the carry flag is changed to logic zero; if c = "0", the value of the carry flag is changed to logic one. flags: c: complemented. no other flags are affected. format: bytes cycles opcode (hex) opc 1 6 ef example: given: the carry flag = "0": ccf if the carry flag = "0", the ccf instruction complements it in the flags register (0d5h), changing its value from logic zero to logic one.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 17 clr ? clear clr dst operation: dst ? "0" the destination location is cleared to "0". flags: no flags are affected. format: bytes cycles opcode (hex) addr mode dst opc dst 2 6 b0 r b1 ir example s : given: register 00h = 4fh, register 01h = 02h, and register 02h = 5eh: clr 00h ? register 00h = 00h clr @01h ? register 01h = 02h, register 02h = 00h in register (r) addressing mode, the statement "clr 00h" clears the destination register 00h value to 00h. in the second example, the statement "clr @01h" uses indirect register (ir) addressing mode to clear the 02h register value to 00h.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 18 com ? complement com dst operation: dst ? not dst the contents of the d estination location are complemented (one's complement); all "1s" are changed to "0s", and vice-versa. flags: c: unaffected. z: set if the result is "0"; cleared otherwise. s: set if the result bit 7 is set; cleared otherwise. v: always reset to "0". d: unaffected. h: unaffected. format: bytes cycles opcode (hex) addr mode dst opc dst 2 6 60 r 61 ir example s : given: r1 = 07h and register 07h = 0f1h: com r1 ? r1 = 0f8h com @r1 ? r1 = 07h, register 07h = 0eh in the first example, destination working register r1 contains the value 07h (00000111b). the statement "com r1" complements all the bits in r1: all logic ones are changed to logic zeros, and vice-versa, leaving the value 0f8h (11111000b). in the second example, indirect register (ir) addressing mode is used to complement the value of destination register 07h (11110001b), leaving the new value 0eh (00001110b).
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 19 cp ? compare cp dst,src operation: dst ? src the source operand is compared to (subtracted from) the destination operand, and the appropriate flags are set accordingly. the contents of both operands are unaffected by the comparison. flags: c: set if a "borrow" occurred (src > dst); cleared otherwise. z: set if the result is "0"; cleared otherwise. s: set if the result is negative; cleared otherwise. v: set if arithmetic overflow occurred, that is, if the operands were of opposite signs and the sign of the result is of the same as the sign of the source operand; cleared otherwise. d: unaffect ed. h: unaffected. format: bytes cycles opcode (hex) addr mode dst src opc dst | src 2 6 a2 r r a3 r lr opc src dst 3 10 a4 r r a5 r ir opc dst src 3 10 a6 r im examples: 1. given: r1 = 02h and r2 = 03h: cp r1,r2 ? set the c and s flags destination working register r1 contains the value 02h and source register r2 contains the value 03h. the statement "cp r1,r2" subtracts the r2 value (source/subtrahend) from the r1 value (destination/minuend). because a "borrow" occurs and the difference is negative, c and s are "1". 2. given: r1 = 05h and r2 = 0ah: cp r1,r2 jp uge,skip inc r1 skip ld r3,r1 in this example, destination working register r1 contains the value 05h which is less than the contents of the source working register r2 (0ah). the statement "cp r1,r2" generates c = "1" and the jp instruction does not jump to the skip location. after the statement "ld r3,r1" executes, the value 06h remains in working register r3.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 20 dec ? decrement dec dst operation: dst ? dst ? 1 the contents of the destination operand are decremented by one. flags: c: unaffected. z: set if the result is "0"; cleared otherwise. s: set if result is negative; cleared otherwise. v: set if arithmetic overflow occurred, that is, dst value is ?128 (80h) and result value is +127(7fh); cleared otherwise. d: unaffected. h: unaffected. format: bytes cycles opcode (hex) addr mode dst opc dst 2 6 00 r 01 ir example s : given: r1 = 03h and register 03h = 10h: dec r1 ? r1 = 02h dec @r1 ? register 03h = 0fh in the first example, if working register r1 contains the value 03h, the statement "dec r1" decrements the hexadecimal value by one, leaving the value 02h. in the second example, the statement "dec @r1" decrements the value 10h contained in the destination register 03h by one, leaving the value 0fh.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 21 di ? disable interrupts di operation: sym (2) ? 0 bit zero of the system mode register, sym.2, is cleared to "0", globally disabling all interrupt processing. interrupt requests will continue to set their respective interrupt pending bits, but the cpu will not service them while interrupt processing is disabled. flags: no flags are affected. format: bytes cycles opcode (hex) opc 1 6 8f example: given: sym = 04h: di if the value of the sym register is 04h, the statement "di" leaves the new value 00h in the register and clears sym.2 to "0", disabling interrupt processing.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 22 ei ? enable interrupts ei operation: sym (2) ? 1 an ei instruction sets bit 2 of the system mode register, sym.2 to "1". this allows interrupts to be serviced as they occur. if an interrupt's pending bit was set while interrupt processing was disabled (by executing a di instruction), it will be serviced when you execute the ei instruction. flags: no flags are affected. format: bytes cycles opcode (hex) opc 1 6 9f example: given: sym = 00h: ei if the sym register contains the value 00h, that is, if interrupts are currently disabled, the statement "ei" sets the sym register to 04h, enabling all interrupts (sym.2 is the enable bit for global interrupt processing) .
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 23 idle ? idle operation idle operation: the idle instruction stops the cpu clock while allowing system clock oscillation to continue. idle mode can be released by an interrupt request (irq) or an external reset operation. flags: no flags are affected. format: bytes cycles opcode (hex) addr mode dst src opc 1 3 6f ? ? example: the instruction idle stops the cpu clock but not the system clock.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 24 inc ? increment inc dst operation: dst ? dst + 1 the contents of the destination operand are incremented by one. flags: c: unaffected. z: set if the result is "0"; cleared otherwise. s: set if the result is negative; cleared otherwise. v: set if arithmetic overflow occurred, that is dst value is +127 (7fh) and result is ?128 (80h); cleared otherwise. d: unaffected. h: unaffected. format: bytes cycles opcode (hex) addr mode dst dst | opc 1 6 re r r = 0 to f opc dst 2 6 20 r 21 ir example s : given: r0 = 1bh, register 00h = 0ch, and register 1bh = 0fh: inc r0 ? ? r0 = 1ch inc 00h ? ? register 00h = 0dh inc @r0 ? r0 = 1bh, register 01h = 10h in the first example, if destination working register r0 contains the value 1bh, the statement "inc r0" leaves the value 1ch in that same register. the next example sh ows the effect an inc instruction has on register 00h, assuming that it contains the value 0ch. in the third example, inc is used in indirect register (ir) addressing mode to increment the value of register 1bh from 0fh to 10h.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 25 iret ? interrupt return iret iret operation: flags ? @sp sp ? sp + 1 pc ? @sp sp ? sp + 2 sym(2) ? 1 this instruction is used at the end of an interrupt service routine. it restores the flag register and the program counter. it also re-enables global interrupts. flags: all flags are restored to their original settings (that is, the settings before the interrupt occurred). format: iret (normal) bytes cycles opcode (hex) opc 1 16 bf
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 26 jp ? jump jp cc,dst (conditional) jp dst (unconditional) operation: if cc is true, pc ? dst the conditional jump instruction transfers program control to the destination address if the condition specified by the condition code (cc) is true; otherwise, the instruction following the jp instruction is executed. the unconditional jp simply replaces the contents of the pc with the contents of the specified register pair. control then passes to the statement addressed by the pc. flags: no flags are affected. format: (1) (2) bytes cycles opcode (hex) addr mode dst cc | opc dst 3 10/12 (3) ccd da cc = 0 to f opc dst 2 10 30 irr notes : 1. the 3-byte format is used for a conditional jump and the 2-byte format for an unconditional jump. 2. in the first byte o f the three-byte instruction format (conditional jump), the condition code and the opcode are both four bits. 3. for a conditional jump, execution time is 12 cycles if the jump is taken or 10 cycles if it is not taken. example s : given: the carry flag (c) = "1", register 00 = 01h, and register 01 = 20h: jp c,label_w ? ? label_w = 1000h, pc = 1000h jp @00h ? pc = 0120h the first example shows a conditional jp. assuming that the carry flag is set to "1", the statement "jp c,label_w" replaces the contents of the pc with the value 1000h and transfers control to that location. had the carry flag not been set, control would then have passed to the statement immediately following the jp instruction. the second example shows an unconditional jp. the statement "jp @00" replaces the contents of the pc with the contents of the register pair 00h and 01h, leaving the value 0120h.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 27 jr ? jump relative jr cc,dst operation: if cc is true, pc ? pc + dst if the condition specified by the co ndition code (cc) is true, the relative address is added to the program counter and control passes to the statement whose address is now in the program counter; otherwise, the instruction following the jr instruction is executed (see list of condition codes). the range of the relative address is +127, ?128, and the original value of the program counter is taken to be the address of the first instruction byte following the jr statement. flags: no flags are affected. format: (1) bytes cycles opcode (hex) addr mode dst cc | opc dst 2 10/12 (2) ccb ra cc = 0 to f notes : 1. in the first byte of the two-byte instruction format, the condition code and the opcode are each four bits. 2. instruction execution time is 12 cycles if the jump is taken or 10 cycles if it is not taken. example: given: the carry flag = "1" and label_x = 1ff7h: jr c,label_x ? pc = 1ff7h if the carry flag is set (that is, if the condition code is true), the statement "jr c,label_x" will pass control to the statement whose address is now in the pc. otherwise, the program instruction following the jr would be executed.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 28 ld ? load ld dst,src operation: dst ? src the contents of the source are loaded into the destination. the source's contents are unaffected. flags: no flags are affected. format: bytes cycles opcode (hex) addr mode dst src dst | opc src 2 6 rc r im 6 r8 r r src | opc dst 2 6 r9 r r r = 0 to f opc dst | src 2 6 c7 r lr 6 d7 ir r opc src dst 3 10 e4 r r 10 e5 r ir opc dst src 3 10 e6 r im 10 d6 ir im opc src dst 3 10 f5 ir r opc dst | src x 3 10 87 r x [r] opc src | dst x 3 10 97 x [r] r
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 29 ld ? load ld (continued) examples: given: r0 = 01h, r1 = 0ah, register 00h = 01h, register 01h = 20h, register 02h = 02h, loop = 30h, and register 3ah = 0ffh: ld r0,#10h ? ? r0 = 10h ld r0,01h ? ? r0 = 20h, register 01h = 20h ld 01h,r0 ? ? register 01h = 01h, r0 = 01h ld r1,@r0 ? ? r1 = 20h, r0 = 01h ld @r0,r1 ? ? r0 = 01h, r1 = 0ah, register 01h = 0ah ld 00h,01h ? ? register 00h = 20h, register 01h = 20h ld 02h,@00h ? ? register 02h = 20h, register 00h = 01h ld 00h,#0ah ? ? register 00h = 0ah ld @00h,#10h ? ? register 00h = 01h,
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 30 register 01h = 10h ld @00h,02h ? ? register 00h = 01h, register 01h = 02, register 02h = 02h ld r0,#loop[r1] ? ? r0 = 0ffh, r1 = 0ah ld #loop[r0],r1 ? register 31h = 0ah, r0 = 01h , r1 = 0ah
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 31 ldc/lde ? load memory ldc/lde dst,src operation: dst ? src this instruction loads a byte from program or data memory into a working register or vice-versa. the source values are unaffected. ldc refers to program memory and lde to data memory. the assembler makes 'irr' or 'rr' values an even number for program memory and odd an odd number for data memory. flags: no flags are affected. format: bytes cycles opcode (hex) addr mode dst src 1. opc dst | src 2 12 c3 r irr 2. opc src | dst 2 12 d3 irr r 3. opc dst | src xs 3 18 e7 r xs [rr] 4. opc src | dst xs 3 18 f7 xs [rr] r 5. opc dst | src xl l xl h 4 20 a7 r xl [rr] 6. opc src | dst xl l xl h 4 20 b7 xl [rr] r 7. opc dst | 0000 da l da h 4 20 a7 r da 8. opc src | 0000 da l da h 4 20 b7 da r 9. opc dst | 0001 da l da h 4 20 a7 r da 10. opc src | 0001 da l da h 4 20 b7 da r notes: 1. the source (src) or working register pair [rr] for formats 5 and 6 cannot use register pair 0 ?1. 2. for formats 3 and 4, the destination address 'xs [rr]' and the source address 'xs [rr]' are each one byte. 3. for formats 5 and 6, the destination address 'xl [rr] and the source address 'xl [rr]' are each two bytes. 4. the da and r source values for formats 7 and 8 are used to address program memory; the second set of values, used in formats 9 and 10 are used to address data memory.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 32 ldc/lde ? load memory ldc/lde (continued) examples: given: r0 = 11h, r1 = 34h, r2 = 01h, r3 = 04h, r4 = 00h, r5 = 60h; program memory locations 0061 = aah, 0103h = 4fh, 0104h = 1a, 0105h = 6dh, and 1104h = 88h. external data memory locations 0061h = bbh, 0103h = 5fh, 0104h = 2ah, 0105h = 7dh, and 1104h = 98h: ldc r0,@rr2 ; r0 ? ? contents of program memory location 0104h ; r0 = 1ah, r2 = 01h, r3 = 04h lde r0,@rr2 ; r0 ? ? contents of external data memory location 0104h ; r0 = 2 ah, r2 = 01h, r3 = 04h ldc * @rr2,r0 ; 11h (contents of r0) is loaded into program memory ; location 0104h (rr2), ; working registers r0,
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 33 r2, r3 ? ? no change lde @rr2,r0 ; 11h (contents of r0) is loaded into external data memory ; location 0104h (rr2), ; working registers r0, r2, r3 ? ? no change ldc r0,#01h[rr4] ; r0 ? ? contents of program memory location 0061h ; (01h + rr4), ; r0 = aah, r2 = 00h, r3 = 60h lde r0,#01h[rr4] ; r0 ? ? contents of external data memory location 0061h ; (01h + rr4), r0 = bbh, r4 = 00h, r5 = 60h
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 34 ldc * #01h[rr4],r0 ; 11h (contents of r0) is loaded into program memory location ; 0061h (01h + 0060h) lde #01h[rr4],r0 ; 11h (contents of r0) is loaded into external data memory ; location 0061h (01h + 0060h) ldc r0,#1000h[rr2] ; r0 ? ? contents of program memory location 1104h ; (1000h + 0104h), r0 = 88h, r2 = 01h, r3 = 04h lde r0,#1000h[rr2] ; r0 ? ? contents of external data memory location 1104h ; (1000h + 0104h), r0 = 98h, r2 = 01h, r3 = 04h
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 35 ldc r0,1104h ; r0 ? ? contents of program memory location 1104h, r0 = 88h lde r0,1104h ; r0 ? ? contents of external data memory location 1104h, ; r0 = 98h ldc * 1105h,r0 ; 11h (contents of r0) is loaded into program memory location ; 1105h, (1105h) ? ? 11h lde 1105h,r0 ; 11h (contents of r0) is loaded into external data memory ; location 1105h, (1105h) ? 11h * these instructions are not supported by masked rom type devices.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 36 ldcd/lded ? load memory and decrement ldcd/lded dst,src operation: dst ? src rr ? rr ? 1 these instructions are used for user stacks or block transfers of data from program or data memory to the register file. the address of the memory location is specified by a working register pair. the contents of the source location are loaded into the destination location. the memory address is then decremented. the contents of the source are unaffected. ldcd references program memory and lded references external data memory. the assemb ler makes ? irr ? an even number for program memory and an odd number for data memory. flags: no flags are affected. format: bytes cycles opcode (hex) addr mode dst src opc dst | src 2 16 e2 r irr examples: given: r6 = 10h, r7 = 33h, r8 = 12h, program memory location 1033h = 0cdh, and external data memory location 1033h = 0ddh: ldcd r8,@rr6 ; 0cdh (contents of program memory location 1033h) is loaded ; into r8 and rr6 is decremented by one ; r8 = 0cdh, r6 = 10h, r7 = 32h (rr6 ? ? rr6 ? 1) lded r8,@rr6 ; 0ddh (contents of data memory location 1033h) is loaded
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 37 ; into r8 and rr6 is decremented by one (rr6 ? ? rr6 ? 1) ; r8 = 0ddh, r6 = 10h, r7 = 32h
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 38 ldci/ldei ? load memory and increment ldci/ldei dst,src operation: dst ? src rr ? rr + 1 these instructions are used for user stacks or block transfers of data from program or data memory to the register file. the address of the memory location is specified by a working register pair. the contents of the source location are loaded into the destination location. the memory address is then incremented automatically. the contents of the source are unaffected. ldci refers to program memory and ldei refers to external data memory. the assembler makes 'irr' even for program memory and odd for data memory. flags: no flags are affected. format: bytes cycles opcode (hex) addr mode dst src opc dst | src 2 16 e3 r irr examples : given: r6 = 10h, r7 = 33h, r8 = 12h, progr am memory locations 1033h = 0cdh and 1034h = 0c5h; external data memory locations 1033h = 0ddh and 1034h = 0d5h: ldci r8,@rr6 ; 0cdh (contents of program memory location 1033h) is loaded ; into r8 and rr6 is incremented by one (rr6 ? ? rr6 + 1) ; r8 = 0cdh, r6 = 10h, r7 = 34h ldei r8,@rr6 ; 0ddh (contents of data memory location 1033h) is loaded ; into r8 and rr6 is incremented by
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 39 one (rr6 ? ? rr6 + 1) ; r8 = 0ddh, r6 = 10h, r7 = 34h
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 40 nop ? no operation nop operation: no action is performed when the cpu executes this instruction. typically, one or more nops are executed in sequence in order to effect a timing delay of variable duration. flags: no flags are affected. format: bytes cycles opcode (hex) opc 1 6 ff example: when the instruction nop is encountered in a program, no operation occurs. instead, there is a delay in instruction execution time.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 41 or ? logical or or dst,src operation: dst ? dst or src the source operand is logically ored with the destination operand and the result is stored in the destination. the contents of the source are unaffected. the or operation results in a "1" being stored whenever either of the corresponding bits in the two operands is a "1"; otherwise a "0" is stored. flags: c: unaffected. z: set if the result is "0"; cleared otherwise. s: set if the result bit 7 is set; cleared otherwise. v: always cleared to "0". d: unaffected. h: unaffected. format: bytes cycles opcode (hex) addr mode dst src opc dst | src 2 6 42 r r 6 43 r lr opc src dst 3 10 44 r r 10 45 r ir opc dst src 3 10 46 r im examples: given: r0 = 15h, r1 = 2ah, r2 = 01h, register 00h = 08h, register 01h = 37h, and register 08h = 8ah: or r0,r1 ? ? r0 = 3fh, r1 = 2ah or r0,@r2 ? ? r0 = 37h, r2 = 01h, register 01h = 37h or 00h,01h ? ? register 00h = 3fh, register 01h = 37h
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 42 or 01h,@00h ? ? register 00h = 08h, register 01h = 0bfh or 00h,#02h ? register 00h = 0a h in the first example, if working register r0 contains the value 15h and register r1 the value 2ah, the statement "or r0,r1" logical-ors the r0 and r1 register contents and stores the result (3fh) in destination register r0. the other examples show the use of the logical or instruction with the various addressing modes and formats.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 43 pop ? pop f rom stack pop dst operation: dst ? @sp sp ? sp + 1 the contents of the location addressed by the stack pointer are loaded into the destination. the stack pointer is then incremented by one. flags: no flags affected. format: bytes cycles opcode (hex) addr mode dst opc dst 2 10 50 r 10 51 ir examples: given: register 00h = 01h, register 01h = 1bh, sp (0d9h) = 0bbh, and stack register 0bbh = 55h: pop 00h ? ? register 00h = 55h, sp = 0bch pop @00h ? register 00h = 01h, register 01h = 55h, sp = 0bch in the first example, general register 00h contains the value 01h. the statement "pop 00h" loads the contents of location 0bbh (55h) into destination register 00h and then increments the stack pointer by one. register 00h then contains the value 55h and the sp points to location 0bch.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 44 push ? push t o stack push src operation: sp ? sp ? 1 @sp ? src a push instruction decrements the stack pointer value and loads the contents of the source (src) into the location addressed by the decremented stack pointer. the operation then adds the new value to the top of the stack. flags: no flags are affected. format: bytes cycles opcode (hex) addr mode dst opc src 2 10 70 r 12 71 ir examples: given: register 40h = 4fh, register 4fh = 0aah, sp = 0c0h: push 40h ? ? register 40h = 4fh, stack register 0bfh = 4fh, sp = 0bfh push @40h ? register 40h = 4fh, register 4fh = 0aah, stack register 0bfh = 0aah, sp = 0bfh in the first example, if the stack pointer contains the value 0c0h, and general register 40h the value 4fh, the statement "push 40h" decrements the stack pointer from 0c0 to 0bfh. it then loads the contents of register 40h into location 0bfh. register 0bfh then contains the value 4fh and sp points to location 0bfh.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 45 rcf ? reset carry flag rcf rcf operation: c ? 0 the carry flag is cleared to logic zero, regardless of its previous value. flags: c: cleared to "0". no other flags are affected. format: bytes cycles opcode (hex) opc 1 6 cf example: given: c = "1" or "0": the instruction rcf clears the carry flag (c) to logic zero.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 46 ret ? return ret operation: pc ? @sp sp ? sp + 2 the ret instruction is normally used to return to the previously executing procedure at the end of a procedure entered by a call instruction. the contents of the location addressed by the stack pointer are popped into the program counter. the next statement that is executed is the one that is addressed by the new program counter value. flags: no flags are affected. format: bytes cycles opcode (hex) opc 1 14 af example: given: sp = 0bch, (sp) = 101ah, and pc = 1234: ret ? pc = 101ah, sp = 0beh the statement "ret" pops the contents of stack pointer location 0bch (10h) into the high byte of the program counter. the stack pointer then pops the value in location 0bdh (1ah) into the pc's low byte and the instruction at location 101ah is executed. the stack pointer now points to memory location 0beh.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 47 rl ? rotate left rl dst operation: c ? dst (7) dst (0) ? dst (7) dst (n + 1) ? dst (n), n = 0?6 the contents of the destination operand are rotated left one bit position. the initial value of bit 7 is moved to the bit zero (lsb) position and also replaces the carry flag. c 7 0 flags: c: set if the bit rotated from the most significant bit position (bit 7) was "1". z: set if the result is "0"; cleared otherwise. s: set if the result bit 7 is set; cleared otherwise. v: set if arithmetic overflow occurred, that is, if the sign of the destination changed during rotation; clea red otherwise. d: unaffected. h: unaffected. format: bytes cycles opcode (hex) addr mode dst opc dst 2 6 90 r 6 91 ir examples: given: register 00h = 0aah, register 01h = 02h and register 02h = 17h: rl 00h ? ? register 00h = 55h, c = "1" rl @01h ? register 01h = 02h, register 02h = 2eh, c = "0" in the first example, if general register 00h contains the value 0aah (10101010b), the statement "rl 00h" rotates the 0aah value left one bit position, leaving the new value 55h (01010101b) and setting the carry and overflow flags.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 48 rlc ? rotate left through carry rlc dst operation: dst (0) ? c c ? dst (7) dst (n + 1) ? dst (n), n = 0?6 the contents of the destination operand with the carry flag are rotated left one bit position. the initial value of bit 7 replaces the carry flag (c); the initial value of the carry flag replaces bit zero. c 7 0 flags: c: set if the bit rotated from the most significant bit position (bit 7) was "1". z: set if the result is "0"; cleared otherwise. s: set if the result bit 7 is set; cleared otherwise. v: set if arithmetic overflow occurred, that is, if the sign of the destination changed during rotation; cleared otherwise. d: unaffected. h: unaffected. format: bytes cycles opcode (hex) addr mode dst opc dst 2 6 10 r 6 11 ir examples: given: register 00h = 0aah, register 01h = 02h, and register 02h = 17h, c = "0": rlc 00h ? ? register 00h = 54h, c = "1" rlc @01h ? register 01h = 02h, register 02h = 2eh, c = "0" in the first example, if general register 00h has the value 0aah (10101010b), the statement "rlc 00h" rotates 0aah one bit position to the left. the initial value of bit 7 sets the carry flag and the initial value of the c flag replaces bit zero of register 00h, leaving the value 55h (01010101b). the msb of register 00h resets the carry flag to "1" and sets the overflow flag.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 49 rr ? rotate right rr dst operation: c ? dst (0) dst (7) ? dst (0) dst (n) ? dst (n + 1), n = 0?6 the contents of the destination operand are rotated right one bit position. the initial value of bit zero (lsb) is moved to bit 7 (msb) and also replaces the carry flag (c). c 7 0 flags: c: set if the bit rotated from the least significant bit position (bit zero) was "1". z: set if the result is "0"; cleared otherwise. s: set if the result bit 7 is set; cleared otherwise. v: set if arithmetic overflow occurred, that is, if the sign o f the destination changed during rotation; cleared otherwise. d: unaffected. h: unaffected. format: bytes cycles opcode (hex) addr mode dst opc dst 2 6 e0 r 6 e1 ir examples: given: register 00h = 31h, register 01h = 02h, and register 02h = 17h: rr 00h ? ? register 00h = 98h, c = "1" rr @01h ? register 01h = 02h, register 02h = 8bh, c = "1" in the first example, if general register 00h contains the value 31h (00110001b), the statement "rr 00h" rotates this value one bit position to the right. the initial value of bit zero is moved to bit 7, leaving the new value 98h (10011000b) in the destination register. the initial bit zero also resets the c flag to "1" and the sign flag and overflow flag are also set to "1".
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 50 rrc ? rotate right through carry rrc dst operation: dst (7) ? c c ? dst (0) dst (n) ? dst (n + 1), n = 0?6 the contents of the destination operand and the carry flag are rotated right one bit position. the initial value of bit zero (lsb) replaces the carry flag; the initial value of the carry flag replaces bit 7 (msb). c 7 0 flags: c: set if the bit rotated from the least significant bit position (bit zero) was "1". z: set if the result is "0" cleared otherwise. s: set if the result bit 7 is set; cleared otherwise. v: set if arithmetic overflow occurred, that is, if the sign of the destination changed during rotation; cleared otherwise. d: unaffected. h: unaffected. format: bytes cycles opcode (hex) addr mode dst opc dst 2 6 c0 r 6 c1 ir examples: given: register 00h = 55h, register 01h = 02h, register 02h = 17h, and c = "0": rrc 00h ? ? register 00h = 2ah, c = "1" rrc @01h ? register 01h = 02h, register 02h = 0bh, c = "1" in the first example, if general register 00h contains the value 55h (01010101b), the statement "rrc 00h" rotates this value one bit position to the right. the initial value of bit zero ("1") replaces the carry flag and the initial value of the c flag ("1") replaces bit 7. this leaves the new value 2ah (00101010b) in destination register 00h. the sign flag and overflow flag are both cleared to "0".
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 51 sbc ? subtract w ith carry sbc dst,src operation: dst ? dst ? src ? c the source operand, along with the current value of the carry flag, is subtracted from the destination operand and the result is stored in the destination. the contents of the source are unaffected. subtraction is performed by adding the two's-complement of the source operand to the destination operand. in multiple precision arithmetic, this instruction permits the carry ("borrow") from the subtraction of the low-order operands to be subtracted from the subtraction of high-order operands. flags: c: set if a borrow occurred (src > dst); cleared otherwise. z: set if the result is "0"; cleared otherwise. s: set if the result is negative; cleared otherwise. v: set if arithmetic overflow occurred, that is, if the operands were of opposite sign and the sign of the result is the same as the sign of the source; cleared otherwise. d: always set to "1". h: cleared if there is a carry from the most significant bit of the low-order four bits of the result; set otherwise, indicating a "borrow". format: bytes cycles opcode (hex) addr mode dst src opc dst | src 2 6 32 r r 6 33 r lr opc src dst 3 10 34 r r 10 35 r ir opc dst src 3 10 36 r im examples: given: r1 = 10h, r2 = 03h, c = "1", register 01h = 20h, register 02h = 03h, and register 03h = 0ah: sbc r1,r2 ? ? r1 = 0ch, r2 = 03h sbc r1,@r2 ? ? r1 = 05h, r2 = 03h, register 03h = 0ah sbc 01h,02h ? ? register 01h = 1ch,
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 52 register 02h = 03h sbc 01h,@02h ? ? register 01h = 15h, register 02h = 03h, register 03h = 0ah sbc 01h,#8ah ? register 01h = 95h; c, s, and v = "1" in the first example, if working register r1 contains the value 10h and register r2 the value 03h, the statement "sbc r1,r2" subtracts the source value (03h) and the c flag value ("1") from the destination (10h) and then stores the result (0ch) in register r1.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 53 scf ? set carry flag scf operation: c ? 1 the carry flag (c) is set to logic one, regardless of its previous value. flags: c: set to "1". no other flags are affected. format: bytes cycles opcode (hex) opc 1 6 df example: the statement scf sets the carry flag to logic one.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 54 sra ? shift right arithmetic sra dst operation: dst (7) ? dst (7) c ? dst (0) dst (n) ? dst (n + 1), n = 0?6 an arithmetic shift-right of one bit positio n is performed on the destination operand. bit zero (the lsb) replaces the carry flag. the value of bit 7 (the sign bit) is unchanged and is shifted into bit position 6. c 7 6 0 flags: c: set if the bit shifted from the lsb position (bit zero) was "1". z: set if the result is "0"; cleared otherwise. s: set if the result is negative; cleared otherwise. v: always cleared to "0". d: unaffected. h: unaffected. format: bytes cycles opcode (hex) addr mode dst opc dst 2 6 d0 r 6 d1 ir examples: given: register 00h = 9ah, register 02h = 03h, register 03h = 0bch, and c = "1": sra 00h ? ? register 00h = 0cd, c = "0" sra @02h ? register 02h = 03h, register 03h = 0deh, c = "0" in the first example, if general register 00h contains the value 9ah (10011010b), the statement "sra 00h" shifts the bit values in register 00h right one bit position. bit zero ("0") clears the c flag and bit 7 ("1") is then shifted into the bit 6 position (bit 7 remains unchanged). this leaves the value 0cdh (11001101b) in destination register 00h.
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 55 stop ? stop operation stop operation: the stop instruction stops the both the cpu clock and system clock and causes the microcontroller to enter stop mode. during stop mode, the contents of on-chip cpu registers, peripheral registers, and i/o port control and data registers are retained. stop mode can be released by an external reset operation or external interrupt input. for the reset operation, the reset pin must be held to low level until the required oscillation stabilization interval has elapsed. flags: no flags are affected. format: bytes cycles opcode (hex) addr mode dst src opc 1 3 7f ? ? example: the statement stop halts all microcontroller operations.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 56 sub ? subtract sub dst,src operation: dst ? dst ? src the source operand is subtracted from the destination operand and the result is stored in the destination. the contents of the source are unaffected. subtraction is performed by adding the two's complement of the source operand to the destination operand. flags: c: set if a "borrow" occurred; cleared otherwise. z: set if the result is "0"; cleared otherwise. s: set if the result is negative; cleared otherwise. v: set if arithmetic overflow occurred, that is, if the operands were of opposite signs and the sign of the result is of the same as the sign of the source operand; cleared otherwise. d: always set to "1". h: cleared if there is a carry from the most significant bit of the low-order four bits of t he result; set otherwise indicating a "borrow". format: bytes cycles opcode (hex) addr mode dst src opc dst | src 2 6 22 r r 6 23 r lr opc src dst 3 10 24 r r 10 25 r ir opc dst src 3 10 26 r im examples: given: r1 = 12h, r2 = 03h, register 01h = 21h, register 02h = 03h, register 03h = 0ah: sub r1,r2 ? ? r1 = 0fh, r2 = 03h sub r1,@r2 ? ? r1 = 08h, r2 = 03h sub 01h,02h ? ? register 01h = 1eh, register 02h = 03h sub 01h,@02h ? ? register 01h = 17h,
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 57 register 02h = 03h sub 01h,#90h ? ? register 01h = 91h; c, s, and v = "1" sub 01h,#65h ? register 01h = 0bch; c and s = "1", v = "0" in the first example, if working register r1 contains the value 12h and if register r2 contains the value 03h, the statement "sub r1,r2" subtracts the source value (03h) from the destination value (12h) and stores the result (0fh) in destination register r1.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 58 tcm ? test complement u nder mask tcm dst,src operation: (not dst) and src this in struction tests selected bits in the destination operand for a logic one value. the bits to be tested are specified by setting a "1" bit in the corresponding position of the source operand (mask). the tcm statement complements the destination operand, which is then anded with the source mask. the zero (z) flag can then be checked to determine the result. the destination and source operands are unaffected. flags: c: unaffected. z: set if the result is "0"; cleared otherwise. s: set if the result bit 7 is s et; cleared otherwise. v: always cleared to "0". d: unaffected. h: unaffected. format: bytes cycles opcode (hex) addr mode dst src opc dst | src 2 6 62 r r 6 63 r lr opc src dst 3 10 64 r r 10 65 r ir opc dst src 3 10 66 r im examples: given: r0 = 0c7h, r1 = 02h, r2 = 12h, register 00h = 2bh, register 01h = 02h, and register 02h = 23h: tcm r0,r1 ? ? r0 = 0c7h, r1 = 02h, z = "1" tcm r0,@r1 ? ? r0 = 0c7h, r1 = 02h, register 02h = 23h, z = "0" tcm 00h,01h ? ? register 00h = 2bh,
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 59 register 01h = 02h, z = "1" tcm 00h,@01h ? ? register 00h = 2bh, register 01h = 02h, register 02h = 23h, z = "1" tcm 00h,#34 ? register 00h = 2bh, z = "0" in the first example, if working register r0 contains the value 0c7h (11000111b) and register r1 the value 02h (00000010b), the statement "tcm r0,r1" tests bit one in the destination register for a "1" value. because the mask value corresponds to the test bit, the z flag is set to logic one and can be tested to determine the result of the tcm operation.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 60 tm ? test u nder mask tm dst,src operation: dst and src this instruction tests selected bits in the destination operand for a logic zero value. the bits to be tested are specified by setting a "1" bit in the corresponding position of the source operand (mask), which is anded with the destination operand. the zero (z) flag can then be checked to determine the result. the destination and source operands are unaffected. flags: c: unaffected. z: set if the result is "0"; cleared otherwise. s: set if the result bit 7 is set; cleared otherwise. v: always reset to "0". d: unaffected. h: unaffected. format: bytes cycles opcode (hex) addr mode dst src opc dst | src 2 6 72 r r 6 73 r lr opc src dst 3 10 74 r r 10 75 r ir opc dst src 3 10 76 r im examples: given: r0 = 0c7h, r1 = 02h, r2 = 18h, register 00h = 2bh, register 01h = 02h, and register 02h = 23h: tm r0,r1 ? ? r0 = 0c7h, r1 = 02h, z = "0" tm r0,@r1 ? ? r0 = 0c7h, r1 = 02h, register 02h = 23h, z = "0" tm 00h,01h ? ? register 00h = 2bh, register 01h = 02h, z = "0"
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 61 tm 00h,@01h ? ? register 00h = 2bh, register 01h = 02h, register 02h = 23h, z = "0" tm 00h,#54h ? register 00h = 2bh, z = "1" in the first example, if working register r0 contains the value 0c7h (11000111b) and register r1 the value 02h (00000010b), the statement "tm r0,r1" tests bit one in the destination register for a "0" value. because the mask value does not match the test bit, the z flag is cleared to logic zero and can be tested to determine the result of the tm operation.
sam87ri instruction set s3c9004/p9004/c9014/p9014 6 - 62 xor ? logical exclusive or xor dst,src operation: dst ? dst xor src the source operand is logically exclusive-ored with the destination operand and the result is stored in the destination. the exclusive-or operation results in a "1" bit being stored whenever the corresponding bits in the operands are different; otherwise, a "0" bit is stored. flags: c: unaffected. z: set if the result is "0"; cleared otherwise. s: set if the result bit 7 is set; cleared otherwise. v: always reset to "0". d: unaffected. h: unaffected. format: bytes cycles opcode (hex) addr mode dst src opc dst | src 2 6 b2 r r 6 b3 r lr opc src dst 3 10 b4 r r 10 b5 r ir opc dst src 3 10 b6 r im examples: given: r0 = 0c7h, r1 = 02h, r2 = 18h, register 00h = 2bh, register 01h = 02h, and register 02h = 23h: xor r0,r1 ? ? r0 = 0c5h, r1 = 02h xor r0,@r1 ? ? r0 = 0e4h, r1 = 02h, register 02h = 23h xor 00h,01h ? ? register 00h = 29h, register 01h = 02h
s3c9004/p9004/c9014/p9014 sam87ri instruction set 6 - 63 xor 00h,@01h ? ? register 00h = 08h, register 01h = 02h, register 02h = 23h xor 00h,#54h ? register 00h = 7fh in the first example, if working register r0 contains the value 0c7h and if register r1 contains the value 02h, the statement "xor r0,r1" logically exclusive-ors the r1 value with the r0 value and stores the result (0c5h) in the destination register r0.

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